Determination of Carbonate and bicorbonate Alkalinity?

Problem. The pH 7.5, CaCOვ alkalinity in 332mg/l. Find the value of carbonate and bicarbonate alkalinity and carbonate and bicarbonate concentration?



Solution: 

As,   pH value <8.2, HCOჳ¯ will exists
So,   Carbonate Alkalinity = 0

Now,
        Total Alkalinity = Carbonate Alkalinity + Bicarbonate Alkalinity
        Given Value, Total Alkalinity =332mg/L
        We get, Carbonate Alkalinity  = 0
        So, Bicarbonate Alkalinity      = Total Alkalinity − Carbonate Alkalinity
                                                         = 332-0
                                                         =332 mg/L


Again,
        Ca(HCOჳ)₂  ⇌Ca²+  ➕ 2HCOჳ¯
        40+(61*2)                       2*61
        =162g                             =122g

        [ HCOჳ¯] = ( 122 / 162*1) mole/L = 0.75 mole/L


        [ COჳ2¯]  = 0 mole/L

Answers :
       Carbonate Alkalinity = 0 mg/L
       Bicarbonate Alkalinity = 332 mg/l
       Carbonate Concentration = 0 mole/L
       Bicarbonate Concentration = 0.75 mole/L



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