Problem 1. Calculate the diameter of a circular pipe that has discharges 2.5 cuset water with a velocity of 6 fps?
Solution:
We Know,
Q =A*V
= (πd2/4)*V
Here, Q=2.5 ft3/s
V= 6fps
⇒ d2= (4Q)/(πV)
= (4*2.5)/(π*6)
=0.53ft 2
∴ d= 0.72ft
Answer: 0.72ft
Problem 2. Determine the diameter of a flow having discharge 1 ft3/s and velocity 2 ft/s.
Solution:
We Know,
Q =A*V
= (πd2/4)*V
Here, Q=1ft3/s
V= 2 ft/s
⇒ d2= (4Q)/(πV)
= (4*1)/(π*2)
=0.0.63ft 2
∴ d= 0.8ft
Answer: 0.8 ft
Problem 3. Find the discharge of a pipe if the velocity of fluid through the pipe is 20 m/s and diameter of pipe is 18 cm?
Solution:
We Know,
Q =A*V
= 20 * (π/4)* 0.18 2
= 0.509 m3/s
Answer: 0.509 m3/s
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